How do you find vertical, horizontal and oblique asymptotes for #(x^2-16)/(x^4)#?

1 Answer
Oct 29, 2016

Answer:

The vertical asymptote is #x=0#
The horizontal asymptote is #y=0#

Explanation:

As you cannot divide by 0, so #x=0# is a vertical asymptote

The degree of the numerator is #># degree of the denominator, there is no oblique asymptote.

Limit#x^2/x^4=1/x^2=0^+#
#x->+-oo#

So #y=0# is a horizontal asymptote

graph{(x^2-16)/x^4 [-6.93, 8.874, -5.09, 2.81]}