# How do you find vertical, horizontal and oblique asymptotes for (x^2-16)/(x^4)?

Oct 29, 2016

The vertical asymptote is $x = 0$
The horizontal asymptote is $y = 0$

#### Explanation:

As you cannot divide by 0, so $x = 0$ is a vertical asymptote

The degree of the numerator is $>$ degree of the denominator, there is no oblique asymptote.

Limit${x}^{2} / {x}^{4} = \frac{1}{x} ^ 2 = {0}^{+}$
$x \to \pm \infty$

So $y = 0$ is a horizontal asymptote

graph{(x^2-16)/x^4 [-6.93, 8.874, -5.09, 2.81]}