# How do you find vertical, horizontal and oblique asymptotes for #(x^2-x+1)/(x-3)#?

##### 1 Answer

Dec 15, 2016

The vertical asymptote is

No horizontal asymptote.

The oblique asymptote is

#### Explanation:

As you cannot divide by

Therefore,

The vertical asymptote is

As the degree of the numerator is

Let's do a long division

Therefore,

The oblique asymptote is

There is no horizontal asymptote. When

graph{(y-(x^2-x+1)/(x-3))(y-x-2)=0 [-41.1, 41.1, -20.56, 20.56]}