# How do you find vertical, horizontal and oblique asymptotes for #y=3/(x-2)+1#?

##### 1 Answer

Nov 9, 2016

The vertical asymptote is

The horizontal asymptote is

There is no oblique asymptote.

#### Explanation:

As we cannot divide by

And

So

There is no oblique asymptote as the degree of the numerator

graph{(y-1-3/(x-2))(y-1)=0 [-14.24, 14.24, -7.12, 7.12]}