# How do you find vertical, horizontal and oblique asymptotes for y =6/x?

Axes x = 0 and y = 0, in both the + and $-$ directions.
xy = 6 represents the rectangular hyperbola, with center at (0, 0), vertices at (sqrt6, sqrt6) and (-sqrt6, -sqrt6).
The foci: $\left(\sqrt{12} , \sqrt{12}\right) \mathmr{and} \left(- \sqrt{12} , - \sqrt{12}\right)$.
The eccentrictyfor a rectangular hyperbola is $\sqrt{2}$.