How do you find vertical, horizontal and oblique asymptotes for #y =6/x#?

1 Answer
Mar 14, 2016

Answer:

Axes x = 0 and y = 0, in both the + and #-# directions.

Explanation:

xy = 6 represents the rectangular hyperbola, with center at (0, 0), vertices at #(sqrt6, sqrt6) and (-sqrt6, -sqrt6#).
The foci: #(sqrt12, sqrt12) and (-sqrt12, -sqrt12)#.
The eccentrictyfor a rectangular hyperbola is #sqrt2#.