# How do you find vertical, horizontal and oblique asymptotes for y= (x^2 - 9)/(x-3)?

Mar 28, 2016

First, factor the numerator: $y = \frac{\left(x + 3\right) \left(x - 3\right)}{x - 3}$
Cancel the factor $x - 3$ from both the numerator and denominator. You are left with $y = x + 3$, a linear function!
If you plot the line $y = x + 3$, there will be NO asymptotes at all, but just a little hole at the point (3,6).