How do you find vertical, horizontal and oblique asymptotes for #y =( x^2-x-6) /( x-2)#?

1 Answer
Apr 9, 2016

Answer:

Vertical asymptote at #x-2=0# and an oblique asymptote #y=x#.

Explanation:

As #y=(x^2-x-6)/(x-2)# looking at the denominator, we have a vertical asymptote at #x-2=0# or #x=2#.

Further as degree of numerator is higher that of denominator by #1#, we will not have any horizontal asymptote.

But we do have a oblique asymptote given by #y=x^2/x=x#

graph{(x^2-x-6)/(x-2) [-10, 10, -10, 10]}