# How do you find vertical, horizontal and oblique asymptotes for y =( x^2-x-6) /( x-2)?

Apr 9, 2016

Vertical asymptote at $x - 2 = 0$ and an oblique asymptote $y = x$.

#### Explanation:

As $y = \frac{{x}^{2} - x - 6}{x - 2}$ looking at the denominator, we have a vertical asymptote at $x - 2 = 0$ or $x = 2$.

Further as degree of numerator is higher that of denominator by $1$, we will not have any horizontal asymptote.

But we do have a oblique asymptote given by $y = {x}^{2} / x = x$

graph{(x^2-x-6)/(x-2) [-10, 10, -10, 10]}