# How do you find x and y intercepts of  -3x + y = 6?

Feb 20, 2017

$x - \text{intercept} = \left(- 2 , 0\right)$

$y - \text{intercept} = \left(0 , 6\right)$

#### Explanation:

All along the $x$-axis, the $y$-value is zero.

All along the $y$-axis, the $x$-value is zero.

TO find the $x$-intercept make $y = 0$

$- 3 x + y = 6$

$- 3 x + 0 = 6$

$x = - 2 \text{ "rarr" the point is } \left(- 2 , 0\right)$

TO find the $y$-intercept make $x = 0$

$- 3 x + y = 6$

$0 + y = 6$

$y = 6 \text{ "rarr" the point is } \left(0 , 6\right)$