How do you FOIL #(5x + 2)(2x - 1)#?

1 Answer
May 24, 2015

Given #(5x+2)(2x-1)#

the First terms are: #(5x)# and #(2x)#
the Outside terms are #(5x)# and #(-1)#
the Inside terms are #(2)# and #(2x)#, and
the Last terms are #(2)# and #(-1)#

#{: ("First ", (5x) xx (2x), " = ", 10x^2), ("Outside", (5x) xx (-1), " = ", -5x), ("Inside", (2) xx (2x), " = ", 4x), ("Last", (2) xx (-1), " = ", -2), ("- - - - - -", "- - - - - -", "- -", "- - - -"), (" ", " ", " ", 10x^2-x-2) :}#