How do you FOIL $(x + 4) (x + 1)$ $(x+4)(x+1)$ ?

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How do you FOIL $(x + 4) (x + 1)$ $(x+4)(x+1)$ ?

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Answer 1 · 2015-05-28T17:09:52

Given $(x + 4) (x + 1)$ $color(red)((x+4))color(blue)((x+1))$

F irst terms: $x \times x = x^{2}$ $color(red)(x)xxcolor(blue)(x) = x^2$
O utside terms: $x \times 1 = 1 x$ $color(red)(x)xxcolor(blue)(1) = 1x$
I nside terms: $4 \times x = 4 x$ $color(red)(4)xxcolor(red)(x) = 4x$
L ast terms: $4 \times 1 = 4$ $color(red)(4)xxcolor(red)(1) = 4$

Sum of FOIL $= x^{2} + 5 x + 4$ $=x^2+5x+4$

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How do you FOIL $(x + 4) (x + 1)$ $(x+4)(x+1)$ ?

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How do you FOIL $(x + 4) (x + 1)$ $(x+4)(x+1)$ ?