How do you FOIL #(x+4)(x+1) #?

1 Answer
May 28, 2015

Given #color(red)((x+4))color(blue)((x+1))#

F irst terms: #color(red)(x)xxcolor(blue)(x) = x^2#
O utside terms: #color(red)(x)xxcolor(blue)(1) = 1x#
I nside terms: #color(red)(4)xxcolor(red)(x) = 4x#
L ast terms: #color(red)(4)xxcolor(red)(1) = 4#

Sum of FOIL #=x^2+5x+4#