# How do you foil  (y+7)(y+4)?

Aug 8, 2015

$\left(y + 7\right) \left(y + 4\right) = \left({y}^{2} + 11 y + 28\right)$

#### Explanation:

Evaluating the product of two binomials using FOIL:

Sum
$\textcolor{w h i t e}{\text{XXXX}}$product of First terms
$\textcolor{w h i t e}{\text{XXXX}}$product of Outside terms
$\textcolor{w h i t e}{\text{XXXX}}$product of Inside terms
$\textcolor{w h i t e}{\text{XXXX}}$product of Last terms

For the given example: $\left(y + 7\right) \left(y + 4\right)$
$\textcolor{w h i t e}{\text{XXXX}}$First terms: $y , y$$\textcolor{w h i t e}{\text{XXXX}}$Product $= {y}^{2}$
$\textcolor{w h i t e}{\text{XXXX}}$Outside terms: $y , 4$$\textcolor{w h i t e}{\text{XXXX}}$Product $= 4 y$
$\textcolor{w h i t e}{\text{XXXX}}$Inside terms: $7 , y$$\textcolor{w h i t e}{\text{XXXX}}$Product $= 7 y$
$\textcolor{w h i t e}{\text{XXXX}}$Last terms: 7, 4color(white)("XXXX")#Product $= 28$

Sum
$\textcolor{w h i t e}{\text{XXXX}}$$= {y}^{2} + 4 y + 7 y + 28$

$\textcolor{w h i t e}{\text{XXXX}}$$= {y}^{2} + 11 y + 28$