# How do you FOIL (Z-2)*(Z-6)?

Jun 18, 2015

Multiply the First terms then Outside terms then Inside terms then Last terms; sum the result to get ${Z}^{2} - 8 Z + 12$

#### Explanation:

Product of
$\textcolor{w h i t e}{\text{XXXX}}$F irst terms: $Z \times Z = {Z}^{2}$
$\textcolor{w h i t e}{\text{XXXX}}$O utside terms: $Z \times \left(- 6\right) = - 6 Z$
$\textcolor{w h i t e}{\text{XXXX}}$I nside terms:$\left(- 2\right) \times Z = - 2 Z$
$\textcolor{w h i t e}{\text{XXXX}}$L ast terms: $\left(- 2\right) \times \left(- 6\right) = 12$

Sum
$\textcolor{w h i t e}{\text{XXXX}}$${Z}^{2} - 6 Z - 2 Z + 12 = {Z}^{2} - 8 Z + 12$