How do you FOIL #(Z-2)*(Z-6)#?

1 Answer
Jun 18, 2015

Answer:

Multiply the First terms then Outside terms then Inside terms then Last terms; sum the result to get #Z^2-8Z+12#

Explanation:

Product of
#color(white)("XXXX")#F irst terms: #Z xx Z = Z^2#
#color(white)("XXXX")#O utside terms: #Z xx (-6) = -6Z#
#color(white)("XXXX")#I nside terms:# (-2) xx Z = -2Z#
#color(white)("XXXX")#L ast terms: #(-2) xx (-6) = 12#

Sum
#color(white)("XXXX")##Z^2 -6Z-2Z+12 = Z^2-8Z+12#