How do you fully factor 4x^2-6xy?

Mar 19, 2018

$2 x \left(2 x - 3 y\right)$

Explanation:

we take out the hcf from each term
so

$h c f \left(4 , 6\right) = 2$

$h c f \left({x}^{2} , x\right) = x$

$\therefore 4 {x}^{2} - 6 x y = 2 x \left(2 x - 3 y\right)$

Mar 19, 2018

$4 {x}^{2} - 6 x y = 2 x \left(2 x - 3 y\right)$

Explanation:

Factor out the common term. Here the common term is 2x.

Thus,

$4 {x}^{2} - 6 x y = 2 x \left(2 x - 3 y\right)$