Question

How do you graph `1.5=y-3x` using the slope and intercept?

Answer 1

see explanation.

Explanation:

Rearrange the given equation into `color(blue)"slope-intercept form"`

That is `color(red)(|bar(ul(color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))`
where m represents the slope and b, the y-intercept.

add 3x to both sides.

`1.5+3x=y-cancel(3x)cancel(+3x)rArry=3x+1.5`

From this equation, slope = 3 and y-intercept = 1.5

To graph : Plot y= 1.5 on the y-axis.

a slope of 3 `=3/1` means 3 units vertically for every 1 unit horizontally.

Now from 1.5 on the y-axis move 3 up and 1 right, plot the point. Repeat for another point and draw a straight line through the 3 points.
graph{3x+1.5 [-10, 10, -5, 5]}