How do you graph #1.5=y-3x# using the slope and intercept?

1 Answer
Aug 18, 2016

see explanation.


Rearrange the given equation into #color(blue)"slope-intercept form"#

That is #color(red)(|bar(ul(color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))#
where m represents the slope and b, the y-intercept.

add 3x to both sides.


From this equation, slope = 3 and y-intercept = 1.5

To graph : Plot y= 1.5 on the y-axis.

a slope of 3 #=3/1# means 3 units vertically for every 1 unit horizontally.

Now from 1.5 on the y-axis move 3 up and 1 right, plot the point. Repeat for another point and draw a straight line through the 3 points.
graph{3x+1.5 [-10, 10, -5, 5]}