# How do you graph #2(y-1) > 3(x+1)#?

##### 1 Answer

Apr 3, 2015

First of all, let's manipulate the expression to isolate the

#2(y-1)=2y-2# #3(x+1)=3x+3# .

So, the expression is equivalent to#2y-2>3x+3#

Add#2# to both sides:

#2y>3x+5#

Divide by#2# both sides:

#y>3/2 x + 5/2#

Now, it's easy to plot the equation

which realize

graph{y>3/2 x + 5/2 [-10, 10, -5, 5]}

Note that the line itself is not part of the solution, because you have the strict inequality and so the set of points