How do you graph #2sin(2x+30°)#?

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Answer 1 · 2018-03-29T02:06:16

As below.

Standard form of sine equation is #y = A sin (Bx - C) + D#

Given equation is #y = 2 sin (2x + 30^@ = 2 sin (2x + (pi/6))#

#Amplitude = |A| = 2#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase shift "= (-C/B) = -(pi/6) / 2 = -pi / 12, (color(green)(pi/12 " to the left"))#

#"Vertical Shift " D = 0#

graph{2 sin (2x + pi/2) [-10, 10, -5, 5]}