Question

How do you graph `2x-1=y`?

Answer 1

See below

Explanation:

This equation is in slope-intercept form so the values for graphing are provided.

The general form is

`color(pink)(| bar(ul(color(black)(y=color(red)mcolor(black)x+color(green)b)) |)`

with `color(red)m` being the slope and `color(green)b` being the y-intercept.

We have:

`y=color(red)2xcolor(green)(-1)`

The y-intercept is at `(0,-1)`

We can then apply the slope. `color(red)m="rise"/"run"=2`, which means we can move two units up for every one unit to the right. Starting from `(0,-1)`, we can move two units up and one unit to the right, so we'll get:

`(0+1,-1+2)=(1,1)`

We can then plot the two points and connect them.

Graphed, it looks like this:

graph{2x-1 [-10, 10, -5, 5]}