How do you graph #2x ^ { 2} + 4y + 3= 5#?
1 Answer
Sep 1, 2017
This is an inverted parabola, with vertex
Explanation:
Given:
#2x^2+4y+3=5#
Subtract
#4y = -2x^2+2#
Divide both sides by
#y = -1/2 x^2+1/2 = -1/2(x^2-1) = -1/2(x-1)(x+1)#
Note that the coefficient of
So it looks like this:
graph{y = -1/2x^2+1/2 [-5.084, 4.916, -2.48, 2.52]}