How do you graph #2x3y+15=0#?
1 Answer
Use one of 3 methods.
Explanation:
There are 3 methods to plot a graph from a given equation:

Plot points: Choose
#x# values and work out#y# values
It is good practice to choose five# x# values. (2 negs, 0 and 2 pos) 
yintercept /gradient method. Change the equation to
#y = mx+c#
Plot the yintercept and use#m = "rise"/"run"# from that point. 
The intercept method. Find both intercepts:
To find the#x# intercept, make#y =0#
To find the#y# intercept, make#x =0#
(This does not work if the line passes through the origin.)
Now plot the points and join with a straight line.
Plot the yintercept at 5.
Count 2 up and 3 to the right, repeat.
Count 2 down and 3 to the left, repeat.
xint:
yint:
Intercepts are at :
The three methods will all give the graph shown:
graph{y = 2/3x+5 [25.17, 14.83, 8.88, 11.12]}