How do you graph #3x+2y=6# by plotting points?

Question

11801 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-22T19:19:07

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) + 2y = 6#

#0 + 2y = 6#

#2y = 6#

#(2y)/color(red)(2) = 6/color(red)(2)#

#y = 3# or #(0, 3)#

Second Point: For #y = 0#

#3x + (2 * 0) = 6#

#3x + 0 = 6#

#3x = 6#

#(3x)/color(red)(3) = 6/color(red)(3)#

#x = 2# or #(2, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 2y - 6)(x^2+(y-3)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}