How do you graph #3x - y =1#?

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Answer 1 · 2018-07-01T18:16:13

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) - y = 1#

#0 - y = 1#

#-y = 1#

#color(red)(-1) xx -y = color(red)(-1) xx 1#

#y = -1# or #(0, -1)#

Second Point: For #y = 2#

#3x - 2 = 1#

#3x - 2 + color(red)(2) = 1 + color(red)(2)#

#3x - 0 = 3#

#3x = 3#

#(3x)/color(red)(3) = 3/color(red)(3)#

#x = 1# or #(1, 2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x - y - 1)(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}