How do you graph #3x-y=3# using intercepts?

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Answer 1 · 2017-09-15T23:53:12

Rearrange the equation in terms of #y#.

Subtract #3x# from both sides:

#- y = -3x + 3#

Multiply by #-1#

#y = 3x - 3#

The #y# axis intercept is #-3# this occurs when #x# is #0#

Rearranging in terms of #x#

#x = (y + 3)/3#

The #x# axis intercept occurs when #y = 0#

#x = (0 + 3)/3 = 1#

The coordinates for graphing are:

#( 0 , -3 ) and ( 1 , 0 )#