# How do you graph #3y+4x=12#?

##### 1 Answer

Feb 15, 2017

This is a straight line through

#### Explanation:

Notice that the terms are linear or constant, so this equation represents a straight line.

We can find the intersections with the

So putting

#3y = 12#

Dividing both sides by

#y=4#

So the line intercepts the

If we instead put

#4x=12#

and hence:

#x=3#

So the

We can now draw our line through these two intercepts:

graph{(4x+3y-12)((x-3)^2+y^2-0.01)(x^2+(y-4)^2-0.01) = 0 [-9.21, 10.79, -2.28, 7.72]}