# How do you graph 4x-3y=20 using the intercepts?

Jul 1, 2018

#### Explanation:

First find the $x$-intercept by putting $y = 0$ i.e. $4 x = 20$ or $x = 5$, which gives us point $\left(5 , 0\right)$

then find $y$-intercept by putting $x = 0$ i.e. $- 3 y = 20$ or $y = - \frac{20}{3} = - 6 \frac{2}{3}$, giving us another point $\left(0 , - 6 \frac{2}{3}\right)$.

Joining two points gives us the graph of $4 x - 3 y = 20$, as shown below

graph{(4x-3y-20)(x^2+(y+20/3)^2-0.03)((x-5)^2+y^2-0.03)=0 [-8.33, 11.67, -7.72, 2.28]}