# How do you graph #5x + y < 7#?

##### 1 Answer

Mar 24, 2018

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

**For:**

**For:**

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y-7)^2-0.125)((x-1)^2+(y-2)^2-0.125)(5x+y-7)=0 [-20, 20, -10, 10]}

Now, we can shade the left side of the line.

The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(5x+y-7)<0 [-20, 20, -10, 10]}