# How do you graph 8(x-5)=(y-3)^2?

##### 1 Answer
Aug 28, 2015

graph{sqrt(8(x-5))+3 [-1.5, 44, -2.5, 21]}

#### Explanation:

To graph $8 \left(x - 5\right) = {\left(y - 3\right)}^{2}$ you will need to isolate $y$ to find its value with respect to $x$:

$8 \left(x - 5\right) = {\left(y - 3\right)}^{2} \rightarrow \sqrt{8 \left(x - 5\right)} = y - 3$

$\rightarrow y = \sqrt{8 \left(x - 5\right)} + 3$

From here you can conclude that $y$'s domain will be x=[5;+oo[ and its range will be y=[3;+oo[

Here are some points through which the curve will go:

(5;3)

(7;7)

(13;11)

(37;19)