# How do you graph 9y<=12x?

To graph an inequality, try to manipulate it into the form $y \setminus \le f \left(x\right)$ (or $y \setminus \ge f \left(x\right)$). Once this is done, the points which solve the inequality will be those under (or above) the graph of the function: in fact, $y = f \left(x\right)$ are exactly the points of the graph. This means that $y \setminus \le f \left(x\right)$ represents all the point below the graph, and vice versa $y \setminus \ge f \left(x\right)$ represents all the point above the graph.
$y \setminus \le \frac{12}{9} x$ which is equivalent to $y \setminus \le \frac{4}{3} x$. So, you only need to draw the $y = \frac{4}{3} x$ line, and take all the part of the plan below the line.
Drawing such a line is quite easy, since it crosses the origin (you can see that $\left(0 , 0\right)$ fits in the equation, as $0 = \frac{4}{3} \cdot 0$), and a second point, chosen as you want. For example, if $x = 3$ you get $y = 4$. So, the line passes through the two points (0,0 and $\left(3 , 4\right)$, and any line is completely determined by two of its point.