# How do you graph and find the discontinuities of (x^2)/(x-1)?

The function is discontinuous at $x = 1$

#### Explanation:

We notice that as $x \to 1$ we have that ${x}^{2} / \left(x - 1\right) \to \infty$. So at $x = 1$ there is a discontinuity.

The graph is as follows

graph{x^2/(x-1) [-20, 20, -10, 10]}