How do you graph and label the vertex and axis of symmetry of #y=-(x-4)^2+8#?

1 Answer
May 19, 2018

#color(red)[vertex=(h, k)=(4,8)]#

the axis of symmetry #color(red)[x=h=4]#

Explanation:

The vertex form of a quadratic function is given by

#color(blue)[y=a(x−h)2+k]#

where (h, k) is the vertex of the parabola.

when written in vertex form

(h, k) is the vertex of the parabola and x = h is the axis of symmetry

the h represents a horizontal shift (how far left, or right the graph has shifted from x = 0)

the k represents a vertical shift (how far up, or down the graph has shifted from y = 0)

the vertex of #color(blue)[y=-(x-4)^2+8]#

#h=4 and k=8#

#color(red)[vertex=(h, k)=(4,8)]#

the axis of symmetry #color(red)[x=h=4]#

show the vertex and the axis if symmetry in the graph below

graph{y=-(x-4)^2+8 [-12.34, 16.14, -2.62, 11.62]}