How do you graph and label the vertex and axis of symmetry #y=2x^2-5x+3#?

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Answer 1 · 2017-07-08T05:44:34

Vertex #(4/5, -1/8)#
Axis of Symmetry #x=5/4#

Given -

#y=2x^2-5x+3#

Vertex

#x=(-b)/(2a)=(-(-5))/(2xx 2)=5/4#

At #x=5/4# value of the function

#y=2(5/4)^2-5(5/4)+3#
#y=50/16-25/4+3=(50-100+48)/16=(98-100)/16=-2/16=-1/8#

Vertex #(4/5, -1/8)#
Axis of Symmetry #x=5/4#

Look at the graph
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