# How do you graph and state the max/min for f(x) = 3x^2 + 4x - 5?

##### 1 Answer
Aug 1, 2015

Graph $f \left(x\right) = 3 {x}^{2} + 4 x - 5$.

#### Explanation:

The graph is a parabola that opens upward $\left(a > 0\right)$.
There is a minimum at vertex,
$x$- coordinate of vertex: $x = - \frac{b}{2 a} = - \frac{4}{6} = - \frac{2}{3}$.
$y$-coordinate of vertex: y = f(-2/3) = 3(4/9) - 8/3 - 5 = 12/9 - 24/9 - 45/9 = (-57/9)
graph{3x^2 + 4x - 5 [-20, 20, -10, 10]}