Question

How do you graph `f(x)=(1/2)^x -3`?

Answer 1

We can start by calculating some solutions :

`f(0)=(1/2)^0-3=1-3=-2`

`f(1)=(1/2)^1-3=0.5-3=-2.5`

`f(2)=(1/2)^2-3=0.25-3=-2.75`

`f(3)=(1/2)^3-3=0.125-3=2.875`

graph{0.5^x-3 [-10, 10, -5, 10]}