How do you graph #f( x ) = 4+ e ^ { - x + 2}#?

1 Answer
Jan 12, 2018

#f(x)# is the standard of #e^-x#, scaled by #e^2# and shifted by 4 units positive ("up") on the #y_#axis.

Explanation:

#f(x)= 4+ e^(-x+2)#

#= 4+ e^2 xx e^-x#

Consider the standard graph of #e^-x# below:

graph{e^-x [-10, 10, -5, 5]}

Now, #f(x)# has this standard graph, scaled by #e^2# and shifted by 4 units positive ("up") on the #y_#axis, as shown below:

graph{4+e^2*e^-x [-20.65, 19.9, -5.77, 14.51]}