Question

How do you graph `F(x)= log_2(x-3)`?

Answer 1

By inversion, `x-3=2^y`, and so, `x=3+2^y`.
The graph rises from `(3, -oo)` to (4, 0) anr rises to `y=oo` through (7, 2), (11, 3), (19, 4),..(

Explanation:

x = 3 is the vertical asymptote and the graph is on the right side of the asymptote, with x > 3.