How do you graph #f(x)=-log_3(-x)#?

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Feb 9, 2018

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Why don't you use a base change?

Explanation:

Meaning that:

#log_a(x)=ln(x)/ln(a)#

We have: #log_3(x)=ln(x)/ln(3)#
while we can say too that #log_3(-x)=ln(-x)/ln(3)#
Therefore, #f(x)=-1/ln(3)(ln(-x)), x lt 0#

Now you can plot #f# as a simple logarithmic (w/ base e) function (just be careful of the new domain and range). If you are familiar with function plotting then it is pretty simple.

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