# How do you graph #f(x)=x^2#?

##### 1 Answer

This is a vertical parabola - a sort of U shape - with vertex at

#### Explanation:

Ultimately, to graph (almost) any function

In our case

In the general case of quadratic functions of form

For example,

with

This is in vertex form: The vertex is at

In our particular example,

graph{(y-x^2)((x+2)^2+(y-4)^2-0.02)((x+1)^2+(y-1)^2-0.02)(x^2+y^2-0.02)((x-1)^2+(y-1)^2-0.02)((x-2)^2+(y-4)^2-0.02)(y*0.00001+x) = 0 [-10.5, 9.5, -2.28, 7.72]}