How do you graph #\frac { 3} { 4} x - 5y = 1#?

Question

729 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-30T04:02:23

See a solution process below:

First, solve the equation for #y#:

#-color(red)(3/4x) + 3/4x - 5y = -color(red)(3/4x) + 1#

#0 - 5y = -3/4x + 1#

#-5y = -3/4x + 1#

#color(red)(1/-5) xx -5y = color(red)(1/-5)(-3/4x + 1)#

#color(red)(1/color(black)(cancel(color(red)(-5)))) xx color(red)(cancel(color(black)(-5)))y = (color(red)(1/-5) xx -3/4x) + (color(red)(1/-5) xx 1)#

#y = (-3)/-20x + (1/-5)#

#y = 3/20x - 1/5#

This equation is in the slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

#y = color(red)(3/20)x - color(blue)(1/5)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Therefore:

The slope is: #color(red)(m = 3/20)#

And the #y#-intercept is: #color(blue)(b = -1/5)# or (0, -1/5)

We can draw the graph as:

graph{y = 3/20x - 1/5 [-2, 2, -1, 1]}