# How do you graph g(x) = (x+3)(x+2)?

Aug 26, 2015

The x-intercepts are at $x = - 3$ and $x = - 2$
The vertex is at $\left(- 2.5 , - 0.25\right)$
Pick a few more points and connect to form graph.

#### Explanation:

If $g \left(x\right) = \left(x + 3\right) \left(x + 2\right)$
then when $g \left(x\right) = 0$ either $x = - 3$ or $x = - 2$

Since this is a parabola in standard position,
the vertex will be midway between the x-intercepts
i.e. at $x = - 2.5$
and $g \left(- 2.5\right) = 0.25$

You could pick a few more random point; for example:
$x = 0 \textcolor{w h i t e}{\text{XXXX")rarrcolor(white)("XX}} g \left(0\right) = 6$
$x = - 4 \textcolor{w h i t e}{\text{XX")rarrcolor(white)("XX}} g \left(- 4\right) = 2$

graph{(x+3)(x+2) [-7.033, 4.067, -1, 4.55]}