Question

How do you graph, label the vertex, axis of symmetry and x intercepts of `y=5(x-2/5)(x-11/5)`?

Answer 1

(`13/10`,`-81/20`)
I hope this help

Explanation:

y=5(x-`2/5`)(x-`11/5`)
1.Apply to distributive property
2. Cancel the common factor of 5
3. Simplify
`5(x-13/10)^2`-`81/20`
`y=5(x-13/10)^2`-`81/20`
x=`13/10`

Use the Vertex Form is y=`a(x-h)^2+k`
a=5
h=`13/10`
k=`-81/20`

Find the vertex (h,k)
(`13/10,-81/20`)
Find p with formula `1/4a`
`1/4*5`=`1/20`
(`13/10`,-4)
x=`-41/10`
Table Vertex
X|Y
-1|22.4
0|4.4
2|-1.6
3|10.4

Vertex: (`13/10`)
Focus:(`13/10`,-4)
Axis of symmetry: x= `13/10`
Directrix: y=`-41/10`