How do you graph -sinx+2?

Apr 19, 2015

You start from $\sin \left(x\right)$
graph{sin(x) [-10, 10, -5, 5]}
You have to apply a symmetry on the x axis and obtain the $- \sin \left(x\right)$ function, which means you have to overturn the graph.
graph{-sin(x) [-10, 10, -5, 5]} and finally you apply a translation adding 2, that means you have to replace the x axis with the line x=2 in the graph
graph{-sin(x) + 2 [-10, 10, -5, 5]}