How do you graph the equation by plotting points #4x - 3y = 6#?

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Answer 1 · 2016-01-27T16:43:15

Look below.

We can easily do that by following the given steps below

Step 1. Take #x=0# and calculate the subsequent value of #y_1# and take procured value as a point #(0,y_1)#.
Step 2. Take #y=0# and calculate the subsequent value of #x_2# and take procured value as a point #(x_2,0)#

For this given problem, we have the equation #4x-3y=6#

So, first let's take #x=0#, which means #-3y=6\implies-cancel{3}^1y=cancel{6}^2\impliesy_1=-2#.
So, the point is #(0,-2)#

Now, let's take #y=0# which means #4x=6\impliescancel{4}^2x=cancel{6}^3\impliesx_2=3/2#
so the point here is #(3/2,0)#.

The is going to look like this. graph{4x-3y=6 [-5, 5, -2.604, 2.606]}