How do you graph the equation by plotting points, y=1/5x-3?

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Answer 1 · 2017-08-17T02:34:15

See a solution process below:

First, we can determine two points on the line by solving the equation for two different values of #x#:

For #x = 0#: #y = (1/5 xx 0) - 3)#

#y = 0 - 3#

#y = -3# or #(0, -3)#

For #x = 5#: #y = (1/5 xx 5) - 3)#

#y = 1 - 3)#

#y = -2# or #(5, -2)#

We can plot these two points on the grid as:

graph{(x^2+(y+3)^2-0.05)((x-5)^2+(y+2)^2-0.05)=0 [-20,20,-10,10]}

Now, draw a straight line through the two points to graph the equation:

graph{(x^2+(y+3)^2-0.05)((x-5)^2+(y+2)^2-0.05)(y-1/5x+3)=0 [-20,20,-10,10]}