How do you graph the equation #y=2x-1#?

1 Answer
Aug 1, 2017

See a solution process below:

Explanation:

First, solve the equation for two points:

For #x = 0#: #y = 2(0) - 1 = 0 - 1 = -1# giving: #(0, -1)#

For #x = 5#: #y = 2(5) - 1 = 10 - 1 = 9# giving: #(5, 9)#

Plot these two points, then draw a straight line through the points:

graph{(y - 2x + 1)((x)^2+(y+1)^2-0.25)((x-5)^2+(y-9)^2-0.25)=0 [-30, 30, -15, 15]}