Question

How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. `y=x^2 +2x -5`?

Answer 1

y = x^2 + 2x - 5

Coordinate of vertex;
`x = -b/2a = -2/2 = -1`
y = f(-1) = 1 - 2 - 5 = -6.

Axis of symmetry x = -1

x- intercepts f(x) = 0.

`D = d^2 = b^2 - 4ac = 4 + 20 = 24 = 4.(6) -> d = +- 2sqr6`
`x1 = -1 + sqr6`
`x2 = -1 - sqr6`