# How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. y=x^2 +2x -5?

May 9, 2015

y = x^2 + 2x - 5

Coordinate of vertex;
$x = - \frac{b}{2} a = - \frac{2}{2} = - 1$
y = f(-1) = 1 - 2 - 5 = -6.

Axis of symmetry x = -1

x- intercepts f(x) = 0.

$D = {d}^{2} = {b}^{2} - 4 a c = 4 + 20 = 24 = 4. \left(6\right) \to d = \pm 2 s q r 6$
$x 1 = - 1 + s q r 6$
$x 2 = - 1 - s q r 6$