How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. # y=x^2-10x+2#?

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Answer 1 · 2015-05-15T18:23:43

x of vertex and axis of symmetry:

#(-b/2a) = 10/2 = 5#

y of vertex: f(5) = 25 - 50 + 2 = -23

x-intercepts : Make #f(x) = x^2 - 10x + 2 = 0.#

#D = d^2 = 100 - 8 = 92 = 4(23) -> d = +- 2sqr23#

x- intercepts:

#x = 5 + (sqr23)/2, and x = 5 - (sqr23)/2#