How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. #y=2x^2 + 1#?
x = -b/2a = 0 -> f(0) = 1.
Coordinate of vertex: x = 0 and y = 1.
Axis of symmetry: x = -b/2a = 0, then Oy is the axis of symmetry.
x-intercepts: (x^2 + 1) is always positive, then there are no x-intercepts. The upward parabola doesn't intercept the x axis.