Question

How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. `y=-3x^2-12x-3`?

Answer 1

`y = -3x^2 - 12x - 3`

Axis of symmetry:`x = (-b/2a) = 12/-6 = -2`
Vertex:
x = -2
y = f(-2) = -12 + 24 - 3 = 9

x-intercepts: `y = -3(x^2 + 4x + 1) = 0`

`D = d^2 = 16 - 4 = 12 -> d = +-2sqrt3`

`x = -2 + sqrt3`
`x = -2 - sqrt3`