How do you graph the function #y=-x+6#?

2 Answers
Jun 22, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 6#

#y = -6 + 6#

#y = 0# or #(6, 0)#

Second Point: For #y = 4#

#y = -4 + 6#

#y = 2# or #(4, 2)#

We can next plot the two points on the coordinate plane:

graph{((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+x-6)((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}

Jun 22, 2018

Answer:

#"see explanation"#

Explanation:

#"one way is to find the intercepts, that is where the graph"#
#"crosses the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=6larrcolor(red)"y-intercept"#

#y=0rArr-x+6=0rArrx=6larrcolor(red)"x-intercept"#

#"plot the points "(0,6)" and "(6,0)#

#"draw a straight line through them for graph"#
graph{(y+x-6)((x-0)^2+(y-6)^2-0.04)((x-6)^2+(y-0)^2-0.04)=0 [-15.79, 15.81, -7.9, 7.9]}