# How do you graph the inequality 10x-8<22 on the coordinate plane?

Aug 16, 2017

See a solution process below:

#### Explanation:

First, solve the inequality for $x$:

$10 x - 8 < 22$

$10 x - 8 + \textcolor{red}{8} < 22 + \textcolor{red}{8}$

$10 x - 0 < 30$

$10 x < 30$

$\frac{10 x}{\textcolor{red}{10}} < \frac{30}{\textcolor{red}{10}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{10}}} x}{\cancel{\textcolor{red}{10}}} < 3$

$x < 3$

We can now graph this by drawing a vertical line at the point $3$ on the x axis. The line will be dashes because this is a **"less than"88 inequality so does not contain the point $3$ as part of the solution.

We will shade to the left of the line because, again, this is a "less than" inequality.

graph{x < 3}