# How do you graph the inequality 2x + 3y > 6?

First draw a lightly dashed version of the line $2 x + 3 y = 6$, which is equivalent to $y = - \setminus \frac{2}{3} x + 2$ (a line with a slope of $- \frac{2}{3}$ and a $y$-intercept of $y = 2$...also note that the $x$-intercept is $x = 3$).
Next, note that the point $\left(0 , 0\right)$ does not satisfy the inequality $2 x + 3 y > 6$. Therefore, shade in the "half-plane" on the other side of the line $2 x + 3 y = 6$ from the side that $\left(0 , 0\right)$ is on. Make sure the line $2 x + 3 y = 6$ remains lightly dashed. It's not part of the solution set.