# How do you graph the inequality x-2y>6?

Draw the straight line $y = \frac{x}{2} - 3$ that passes through $\left(6 , 0\right) \mathmr{and} \left(0 , - 3\right)$. Shade the region below this line in the negative y-direction, sans this line, Enter #x-2 y > 6 therein. .
The given inequality is equivalent to $y < \frac{x}{2} - 3$
For any point (x, y) below this line in the negative y-direction. $y < \frac{x}{2} - 3$, and so, $x - 2 y > 6$..